[ October 9, 2001 ]
How many palindromes can you find
that are the products of two pandigital numbers ?

Two pandigital numbers 1023687954 and 2901673548 which on their own defy all palindromicy (any rearrangements of their digits never produces palindromes) yet when multiplied together produce surprisingly this palindrome 2970408257528040792 .

There exists lots and lots more similar solutions.
Can you find them ? How many are there in total ?
[ Final score is 1277 ] _{January 2, 2009}
In collaboration with Peter Kogel.
I created a webpage twopan.htm where I display
all the palindromic products that we encountered.

Can you discover the first palindromes being the products
of three, four and more pandigitals ?

Peter Kogel (email) wrote [ October 28, 2008 ]

So far the closest I have come to success are the following :

38766662887833033878826666783 = 1264358097 x 8257640913 x 3713063103 37766638930788088703983666773 = 5769810243 x 8759416023 x 747259857 37766629851728882715892666773 = 2605894371 x 6291457803 x 2303563221 37766607369477677496370666773 = 1965024387 x 5610249387 x 3425767317 37766578522759495722587566773 = 1348296057 x 2659034781 x 10534122369

The problem is somewhat challenging to say the very least !
I began my search at a purely random point to test the efficiency
of my program and to try to gauge how long such a search might take.
Based on the progress I have made so far, I must confess that I'll
probably abandon the search, unless I can either think of a way
to radically improve the efficiency of my search algorithm or am
very lucky. I can see no reason why such a solution should not exist.
Perhaps one of your other readers can shed some light on the subject.

WONplate 97 investigated the ninedigital version of this topic !